x^2+200x-240000=0

Solution for x^2+200x-240000=0 equation:

x^2+200x-240000=0

a = 1; b = 200; c = -240000;
Δ = b2-4ac
Δ = 2002-4·1·(-240000)
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1000000}=1000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-1000}{2*1}=\frac{-1200}{2}
=-600
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+1000}{2*1}=\frac{800}{2}
=400
$